а ^lArray.add[ $anotherArray ] можно?

AK666 07.10.2019 00:55 / 07.10.2019 00:58

$arr[^Array::create[]]

^dRoot.menu{
 $dChild[^table::sql{SELECT ID, ... FROM aTableChild WHERE RootID = $dRoot.ID}]
 ^arr.add[
     $.ID[$Root.ID]
     $.F1[$Roor.F1]
     $.Chld[$dChild]

     ^dChild.menu{
      $subChild[^table::sql{SELECT ID, ... FROM aTableSubChild WHERE ChildID = $dChild.ID}]
      $.subChild[$subChild]

      $subArr[^Array::create[]]
      ^subArr.add[
        $.ID[$subChild.ID]
        $.F2[$subChild.F2]
      ]
      $.subChildArray[$subArr]
    }
  ]
}

^json_string[$arr]

subChild - с данными
subChildArray - пустой

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